Pressure in Popcorn
- isaiahamanuel20
- Apr 26, 2018
- 1 min read
Following a certain set of procedures the pressure in popcorn lab yielded some very interesting results:
Materials:
A bag of unpopped kernels
graduated cylinder
test tube
bunsen burner
vegetable oil
Procedure:
First use water displacement to find the volume of popcorn
Then cover the cylinder with vegetable oil and weigh it.
After weighing it, heat it under the bunsen burner then weigh it again.
Here are the results below:


MY PROCESS (WORK)
5 Ml
111.2/109.54
1.67 times 1/18= 0.093 moles
P=nRT/v
(0.093)(0.0821)(498)(.0.0055)=691.3/37
18.68 atm
Now using this data, we have to find the pressure where each kernel pops. We have found everything we need except the amount of moles of kernels that we have, which we are easily able to find (0.093 moles). After we find that, all we need to do is use the ideal gas law and we have the pressure for each kernel 18.68 atm.
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